| Mathematics - 1801
...30 • Or 6 : i :: 28,2744 : 4-7124 Or 3 : 30 :: -05236X9 : 4'7^4 36 4-7124 the answer. RULE a.* . **From 8 times the chord of half the arc subtract the chord of the whole arc, and** ~ of the remainder "-'ill be the length of the arc nearly. 2. The * DEMONSTRATION. Let the radius OD~r,... | |
| Anthony Nesbit, W. Little - Measurement - 1822
...French iaticians, to 128. PROBLEM XII. To Jtnd the length of the arc of a circle. RULE I. By the Pen. **8 times the chord of half the arc subtract the chord of the whole** ate, and i of the remainder will be the length of the arc, nearly. Note 1. Half the chord of the whole... | |
| Anthony Nesbit - Measurement - 1824 - 434 pages
...Bonnycastle's As* 'ronomy, page 277. PROBLEM XIV. To find the length of any arc of a circle. RULE I. **From 8 times the chord of half the arc subtract the chord of the whole arc, and** }, of the remainder . will be the length of the arc, nearly. Kote. Half the chord of the whole arc,... | |
| John Nicholson - Industries - 1825 - 795 pages
...feet.,. 3-1416 9 As 180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 39 : : '05236 x 9 : 47124 90 47124 the **answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and** ' of the remainder will be the length of viie arc nearly. Ex. 2. The chord AB (Proli. 8.) of the whole... | |
| John Nicholson (civil engineer.) - Great Britain - 1825 - 795 pages
...180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 30 : : '05236 X 9 : 4-7124 90 4*7124 the answer. R'i!,- **2. From 8 times the chord of half the arc subtract the chord of** tbe whole arc, and ' of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prol.... | |
| William Galbraith - Astronomy - 1827 - 322 pages
...radius of the circle multiplied by 0.0174533 and by the number of degrees in the arc. Or, from eight **times the chord of half the arc subtract the chord of the whole arc,** one third of this remainder is the length of the arc nearly. 9. Circular Sector. — The area is equivalent... | |
| John Nicholson (Civil engineer) - Building - 1830 - 182 pages
...feet.. 3-1416 9 As 180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3: 30 : : 105236 x 9:47124 90 47124 the **answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and** .1 of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the whole... | |
| Samuel YOUNG (of Manchester.) - 1833
...in the same square whose diameter is 24. PROBLEM IX. To find the length of a Circular Arc. RULE 1. **From 8 times the chord of half the arc subtract the chord of the whole arc, and** ^ of the difference will be the length of the arc, nearly. RULE 2. Multiply the number of degrees in... | |
| Francis Walkingame - 1833
...5. The area X'6S6G197) Problem 9- Toßnd the length of a circular arc RULE 1. From 8 times Fig. 8. **the chord of half the arc subtract the chord of the whole arc, and** ¿ of the difference will be the length of the arc, nearly. That is ADx8— AB -т-3=.агс ADB. NOTE.... | |
| Olinthus Gregory - Mathematics - 1834 - 427 pages
...4400 Add } s* = 80 Area of the dodecagon = 4480 : the true area is 4478-46. 3. Length of circular arc. **From 8 times the chord of half the arc, subtract the chord of the whole arc, and** 4 of the remainder will be the length of the arc, nearly. Note. — The chord of half the arc is equal... | |
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