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" Or, from 8 times the chord of half the arc, subtract the chord of the whole arc, and $ of the remainder will be the length of the arc, nearly. "
Cyclopedia of Architecture: Historical, Descriptive, Typographical ... - Page 285
by Robert Stuart - 1854
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Study of Steam and the Marine Engine for Young Sea Officers in H.M. Navy ...

S. M. Saxby - Marine engines - 1862 - 179 pages
...radius multiplied by the length of the arc equals the area. KB. To find the length of an arc. From eight times the chord of half the arc subtract the chord of the whole arc, and take one third the remainder for the length of the arc nearly. For the segment or any part of a circle...
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Mathematics for Practical Men: Being a Common-place Book of Principles ...

Olinthus Gregory - 1863
...4400 Add i s' = 80 Area of the dodecagon = 4480 : the true area is 4478-46. 3. Length of circular arc. From 8 times the chord of half the arc, subtract the chord of the whole arc, and $ of the remainder will be the length of the arc, nearly. Note. — The chord of half the arc is equal...
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Rudimentary treatise on mensuration and measuring

Thomas Baker (C.E.) - 1865
...radius to its length. CASE II. — When the chord of half and the whole arc are given. RULE II. — From 8 times the chord of half the arc subtract the chord of the whole arc, and take \ of the remainder for the lungth of the arc nearly. FORMULAE. (See last figure.) Put r = radius...
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Loftus's Inland Revenue Officers' Manual: a guide to the duties and ...

William Harris JOHNSTON - 1865
...Draw the diameter and the chord of the arc. Then, if the aro be less than a semi-circle, from eight times the chord of half the arc subtract the chord of the whole arc ; one-third of the remainder will be the length of the arc, nearly. In order to determine the chord...
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A Practical Workshop Companion for Tin, Sheet Iron, and Copper Plate Workers...

Leroy J. Blinn - Sheet-metal work - 1866 - 178 pages
...2 = 820.28, &c.,feet the diameter. To find the Length of any arc of a circle. RULE. — From eight times the chord of half the arc, subtract the chord of the whole arc, and one-third of the remainder will be the length nearly. 9 • Required the length of the arc ABO, fig....
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Elements of Geometry and Trigonometry

C. Davies - 1867
...arc of a circle when the chord and radius are givenRULE I Find the chord of half the arcII From eight times the chord of half the arc, subtract the chord of the whole arc, and divide the remainder by 3, and the quotient will be the length of the arc, nearlyEXAMPLES 1 The chord...
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The Normal Elementary Geometry: Embracing a Brief Treatise on Mensuration ...

Edward Brooks - Geometry - 1868 - 275 pages
...25 inches? Ans. 14.2441 inches. 16. When the chord and chord of the half arc are given. RULE.—From 8 times the chord of half the arc, subtract the chord of the whole arc, and divide the remainder by 3. 1. The chord of an arc is 96 inches, and the chord of half the arc is 60...
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Elementary and Practical Instructions on the Science of Railway Construction

Sir Rowland Macdonald Stephenson - Railroads - 1869 - 262 pages
...radius to its length. CASE II. — When the chord of half and of the whole arc are given. RULE II. — From 8 times the chord of half the arc subtract the chord of the whole arc, and take J of the remainder for the length of the arc nearly. 1. To find the length of an arc of 30 degrees,...
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Mensuration for Beginners: With Numerous Examples

Isaac Todhunter - Measurement - 1869 - 296 pages
...arc being known, and also the chord of half the arc, to find the length of the arc. RULE. From eight times the chord of half the arc subtract the chord of the whole arc, and divide the remainder by three. This Rule is not cxict ; it gives the length of the arc smaller than...
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Explanatory mensuration for the use of schools

Alfred Hiley - 1871
...circle less than a semicircle, when the chord of the arc and the diameter of the circle are given. From 8 times the chord of half the arc subtract the chord of the whole arc ; divide the remainder by 3, and the quotient is the length of the arc, nearly. Note 1. — The answers...
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