 | Robert Shirtcliffe - Gaging - 1740 - 322 pages
...(by Cor. to the laft Whence we have the following Rule to meafure any Circle whofe Diameter is given. Multiply the Square of the Diameter by ,7854, and the Product is nearly the Area thereof. Cor. 3. If C be the Circumference of any Circle, then fince 3.1416=4*?: 1... | |
 | Thomas Hornby (land surveyor.) - Surveying - 1827 - 318 pages
...RULE 1st. Multiply half the Circumference by half the Diameter, and the product is the area. RULE 2. Multiply the square of the diameter by .7854 and the product is the area. EXAMPLE. Required the area of the circle whose diameter AB is 600 links. (By Prob. 7th,) 600 x 3.1416... | |
 | A. Turnbull - Arithmetic - 1836 - 368 pages
...t,f the above methods will give a result sufficiently correct fur all practical purposes. 6. To find the area of a circle, multiply the square of the diameter by .7854 ; or multiply half the circumference by half the diameter ; or multiply the circumference and diameter... | |
 | Mathematics - 1836 - 488 pages
...number of degrees in the arc; so is the circumference of the circle, to the length of the arc. To find the area of a circle. Multiply the square of the diameter by the decimals .7854. Or, multiply half the diameter into half the circumference. Or, multiply the whole... | |
 | William Templeton - Locomotives - 1841 - 112 pages
...balance. THE AREA OF THE VALVE. To find the area, or number of square inches in a valve. RULE. — Multiply the square of the diameter by .7854 and the product is the area, — thus, 2.5" = 6.25 X .7854 = 4.9087 the area. THE SMOKE BOX. The shell of the smoke box is of wrought... | |
 | Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...inscribed in a circle -.—Multiply the diameter by .707016. tr the circumference by .255079. 5. To find the area of a circle :— Multiply the square of the diameter by .785398, or tit* tquate of the circumference by .079577525. 6. Te lind the diameter of a elide:—... | |
 | Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...inscribed in a circle : — Multiply the diameter by .707016, or the circumference by .2251)79. 5. To find the area of a circle -.—Multiply the square of the diameter by .785398, or the square of the circumference by .0711577525. 6. To Hud the diameter ofa circle: —... | |
 | Roswell Chamberlain Smith - Arithmetic - 1843 - 320 pages
...inscribed in a circle;—Multiply the diameter by .707016, or the circumference by .225079. 5. To find the area of a circle -.—Multiply the square of the diameter by .785398, or tks tquare of the circumference by .079577525. 6. To find the diameter of a circle:—Multiply... | |
 | William Templeton (engineer.) - 1848 - 118 pages
...balance. THE AREA OF THE VALVE. To find the area, or number of square inches in a ralve. RULE. — Multiply the square of the diameter by .7854 and the product is the area, — thus, 2.5" = 6.25 X .7854 = 4.9087 the area. THE SMOKE BOX. The shell of the smoke box is of wrought... | |
 | Roswell Chamberlain Smith - Arithmetic - 1850 - 314 pages
...inscribed in a circle '.—Multiply the diameter by .707016, tr the circumference by .225079. 5. To find the area of a circle '.—Multiply the square of the diameter by .785398, or the \quare of the circumference by .079577525. 6. To find the diameter of a circle: —... | |
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To find the area of a circle, multiply the square of the diameter by .7854. 
