| Mathematics - 1801 - 658 pages
...30 • Or 6 : i :: 28,2744 : 4-7124 Or 3 : 30 :: -05236X9 : 4'7^4 36 4-7124 the answer. RULE a.* . From 8 times the chord of half the arc subtract the chord of the whole arc, and ~ of the remainder "-'ill be the length of the arc nearly. 2. The * DEMONSTRATION. Let the radius OD~r, and sine DB ,.... | |
| Samuel Webber - Mathematics - 1808 - 466 pages
...180 : 30 Or 6 : 1 : : 282744 ; 4'7124 Or a : 30 : : '05236x9 : 4'7124 36 4'? 124 the answer. RULE*. From 8 times the chord of half the arc subtract the...the whole arc, and | of the remainder will be. the kpgth, of the arc nearly. * DEM0NSTRATI0N. Let the radius CA=r, and sine AP ««. Then will the chord... | |
| Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...French iaticians, to 128. PROBLEM XII. To Jtnd the length of the arc of a circle. RULE I. By the Pen. 8 times the chord of half the arc subtract the chord of the whole ate, and i of the remainder will be the length of the arc, nearly. Note 1. Half the chord of the whole... | |
| Anthony Nesbit - Surveying - 1824 - 476 pages
...Bonnycastle's As* 'ronomy, page 277. PROBLEM XIV. To find the length of any arc of a circle. RULE I. From 8 times the chord of half the arc subtract the...remainder . will be the length of the arc, nearly. Kote. Half the chord of the whole arc, the chord of half the arc, and the versed sine are sides of... | |
| William Galbraith - Astronomy - 1827 - 412 pages
...radius of the circle multiplied by 0.0174533 and by the number of degrees in the arc. Or, from eight times the chord of half the arc subtract the chord of the whole arc, one third of this remainder is the length of the arc nearly. 9. Circular Sector. — The area is equivalent... | |
| John Nicholson (Civil engineer) - Building - 1830 - 240 pages
...radius being 9 feet.. 3-1416 9 As 180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3: 30 : : 105236 x 9:47124 90 47124 the answer. Rule 2. From 8 times the chord...half the arc subtract the chord of the whole arc, and .1 of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the whole... | |
| Samuel YOUNG (of Manchester.) - 1833 - 272 pages
...in the same square whose diameter is 24. PROBLEM IX. To find the length of a Circular Arc. RULE 1. From 8 times the chord of half the arc subtract the chord of the whole arc, and ^ of the difference will be the length of the arc, nearly. RULE 2. Multiply the number of degrees in the arc... | |
| Francis Walkingame - 1833 - 204 pages
...5. The area X'6S6G197) Problem 9- Toßnd the length of a circular arc RULE 1. From 8 times Fig. 8. the chord of half the arc subtract the chord of the whole arc, and ¿ of the difference will be the length of the arc, nearly. That is ADx8— AB -т-3=.агс ADB. NOTE. Half... | |
| Olinthus Gregory - Mathematics - 1834 - 484 pages
...4400 Add } s* = 80 Area of the dodecagon = 4480 : the true area is 4478-46. 3. Length of circular arc. From 8 times the chord of half the arc, subtract the chord of the whole arc, and 4 of the remainder will be the length of the arc, nearly. Note. — The chord of half the arc is equal... | |
| Ireland commissioners of nat. educ - 1834 - 370 pages
...series, let it be assumed =: d V — ; - т ¿' « — « ^ n\f dv, and we get RULE II. From eight times the chord of half the arc, subtract the chord of the whole arc, and it will be found ^)+ -) = V dv d I X - + « = V* r This being expanded, we get S*^ *cA 8rf2ffT / By... | |
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