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action angles applied arms axis body bottom called carried cause centre circle colour common consequently consists construction contain continued covered cylinder described diameter direction distance draw edge effect employed engine equal fall feet figure fitted fixed force four frame give given half heat hole horizontal hour inches increased iron joint kind lead length less lever lower machine manner means metal method mill minute motion moving necessary operation pass piece pinion pipe piston placed plate position pounds pressure prevent produce proper proportion pump quantity raised receive represented rest rollers round screw shaft side space spindle spring square steam steel stone sufficient supported surface taken teeth thickness turned upper valve varnish vertical vessel wall weight wheel whole wood
Page 684 - Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area.
Page 683 - Sides given. The square of the hypotenuse is equal to both the squares of the two legs. Therefore, 1.
Page 676 - Prob. 7. Through a given point C, to draw a line parallel to a given line AB.
Page 59 - He broke a rope of two inches in circumference ; though, from his awkward manner, he was obliged to exert four times more strength than was necessary. He lifted a rolling stone of eight hundred pounds' weight with his hands only, standing in a frame above it, and taking hold of a chain fastened thereto.
Page 715 - ... arrangement on the rack. Each letter or stamp must be tried as to its heat, by imprinting its mark on the raw side of a piece of waste leather. A little practice will enable the workman to judge of the heat. The tool is now to be pressed downwards on the gold leaf, which will, of course, be indented and show the figure imprinted on it. The next letter or stamp is now to be taken and...
Page 115 - ... 4. Divide the circumference of the wheel in feet by the velocity of its floats in feet per second, and the quotient will be the number of seconds in which the wheel turns round.
Page 764 - ... easy and simple in the extreme, and so evidently efficient in its application, that it cannot but excite surprise that, in the present highly improved state of our manufactures, such a communication should be made as a discovery entirely new. Instead, therefore, of the customary mode of hardening the blade from the anvil, let it be passed immediately from the hands of the forger to the grinder ; a slight application of the stone will remove the whole of the scale or coating, and the razor will...
Page 147 - ... and a second quantity will be had. Multiply the area of the millstone by the weight of a cubic foot of the same stone, for a third quantity. Multiply the first quantity by the second, and divide the product by the third, and the quotient will be the weight required. 2. To find the number of cubic feet in the turning millstone, supposing it to have no eye :—From the weight of the spindle and lantern subtract the quantity found by the preceding rule, for the first number. Subtract this first...