 | Thomas Keith - 1817 - 306 pages
...frustum of a cone, multiply half the sum of the perimeters of the two ends by the slant height, and the product will be the convex surface ; to which add the areas of the two ends, and the sum will be the whole surface of the frustum. * See the Note to Problem VII. page 106.... | |
 | Anthony Nesbit - Surveying - 1824 - 476 pages
...may be found thus : Multiply half the sum of the perimeters of the two ends* by the slant height, and the product will be the convex surface; to which add the areas of the ends, and the sum will be the whole surface of the frustum. EXAMPLES. 1. What is the solidity of the... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...sum of the circumferences of the two bases, for the convex surface (Book VIII. Prop. IV.) : to whicfi add the areas of the two bases, when the entire surface is required. 1. To find the convex surface of the frustum of a cone, the side of the frustum being 12i feet, and... | |
 | Adrien Marie Legendre - Geometry - 1837 - 376 pages
...half tlie sum of the circumferences of the two bases, for the convex surface (Book VIII. Prop. IV.) : to which add the areas of the two bases, when the entire surface is required. 1. To find the convex surface of the frustum of a cone, the side of the frustum being 12i feet, and... | |
 | Charles Davies - Geometrical drawing - 1840 - 264 pages
...RULE. Add together the circumferences of the two bases, and multiply the sum by half the slant height of the frustum ; the product will be the convex surface, to which add the areas of the bases, when the entire surface is required. EXAMPLES. 1. What is the convex surface of the frustum... | |
 | Charles Davies - Geometrical drawing - 1840 - 262 pages
...circumference of the base by the altitude, and the product will be the convex surface ; and to this, add the areas of the two bases, when the entire surface is required. EXAMPLES. 1. What is the entire surface of the cylinder in which AB, the diameter of the base is 12... | |
 | J. M. Scribner - Measurement - 1844 - 130 pages
...together the circumferences of the two ends, and multiply the sum by J the slant height of the frustrum ; the product will be the convex surface : to which...the two bases when the entire surface is required. This rule is precisely the same as that for a frustrum of a pyramid (Art. 41;) and if a cone be considered... | |
 | Charles Davies - Geometrical drawing - 1846 - 254 pages
...cone ? Add together the circumferences of the two bases, and multiply the sum by half the slant height of the frustum ; the product will be the convex surface, to which add the areas of the bases, when the entire surface is required. EXAMPLES. 1. What is the convex surface of the frustum... | |
 | J. M. Scribner - Mechanical engineering - 1849 - 286 pages
...together the circumferences of the two ends, and multiply the sum by i the slant of the frustrum ; the product will be the convex surface : to which...NOTE. This rule is precisely the same as that for a frustrum of a pyramid, and -fa cone be considered as a pyramid of an infinite number of sides, it is... | |
 | Charles Davies - Trigonometry - 1849 - 372 pages
...half the sum of the circumferences of the two bases, for the convex surface (Book VIII. Prop. IV.): to which add the areas of the two bases, when the entire surface is required. 1. To find the convex surface of the frusium of a cone, thfi side of the frustum being 12£ feet, and... | |
| |
... the product will be the convex surface, to which add the areas of the bases, when the entire surface is required (Bk. 
