| Mathematics - 1801
...the street. • t Ans. 76- 1 2333 35 feet. PROBLEM IV. 7o f:nd tlie area of a trapezoid. • RULE.* **Multiply the sum of the two parallel sides by the...between them, and half the product will be the area.** • EXAMPLES. * DEMONSTRATION. or (because B»=DE) =-, .-. A ABD+ A BCD, or , , , ABxDE , DCxDE the... | |
| James Thompson - Arithmetic - 1808 - 172 pages
...trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. RULE — Multiply the sum of the **parallel sides by the perpendicular distance between them, and half the product •will be the area.** EXAMPLES. 13. Required the area of a trapezoid whose parallel sidef »re 25 feel 6 inches, and 18 feet... | |
| Anthony Nesbit, W. Little - Measurement - 1822
...the grain? Ant. 97.3383 bushels. PROBLEM VII. To Jind the area of a trapezoid. RULE. • By the Pen. **Multiply the sum of the two parallel sides by the...between them, and half the product will be the area** in square inches. Divide this area by 2 82, 231, and 2150.42, and the respective quotients will be... | |
| Anthony Nesbit - Measurement - 1824 - 434 pages
...Ans. 1131^.2 in. 9 pa. PROBLEM VIII. To find the area of a Irapezoid. RULE. Multiply the sum of the **parallel sides by the perpendicular distance between them, and half the product will be the area.** Or, half the sum of the sides multiplied by their distance will give the area. EXAMPLE. 1. What is... | |
| John Nicholson - Electronic book - 1825 - 795 pages
...when the squre of AB has been subtracted. 63 I 189 3 1 189 Prot. 4. To find the Area ofaTrapezoid. **Multiply the sum of the two parallel sides by the...perpendicular distance AP or CN is 9 : required the area. 7** 12 19 9 171 85£ the area. Prob. 5. To find the Area of a Trapezium. Case for any trapezium. — Divide... | |
| John Nicholson (civil engineer.) - Great Britain - 1825 - 795 pages
...Prob. 4. To find the Area of aTrapezoid. Multiply the sum of the two parallel sides by the perpendini **distance between them, and half the product will be...In a trapezoid, the parallel sides are AB 7, and CD** I: and the perpendicular distance AP or CN is 9 : required the area, 7 12 19 9 171 85$ the area. Pfot.... | |
| Thomas Hornby (land surveyor.) - Surveying - 1827 - 270 pages
...16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply the sum of the **parallel sides by the perpendicular distance between them, and half the product will be the area.** EXAMPLE. Required the area of the trapezoid AB CD, whose parallel sides AB and DC are 800 and 640 links... | |
| John Bonnycastle - Geometry - 1829 - 252 pages
...trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the **parallel sides by the perpendicular distance between them, and half the product will be the** EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides AB and DC are 321.51 and 214.24,... | |
| John Nicholson (Civil engineer) - Building - 1830 - 182 pages
...when the square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. **Multiply the sum of the two parallel sides by the...perpendicular distance AP or CN is 9 : required the area. 7** 12 19 9 171 855 the area. Prob. 5. To find the Area of a Trapezium. Case for any trapezium.— Divide... | |
| Edinburgh encyclopaedia - 1830
...quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply the sum of the **parallel sides by the perpendicular distance between them, and half the product** is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities draw AE, CF at right... | |
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