| Mathematics - 1801
...'Multiply the radius, or half the diameter, by half the arc of the sector for the area. Or, take •£ **of the product of the diameter and arc of the sector. NOTE. The arc may be found by Problem** X. •c •"—" • RULE 2.f As 360 is to the degrees in the arc of the sector, so is the whole area... | |
| Thomas Hodson - Education - 1806
...CIRCLE. Fig.22. RULE i. Multiply the radius by half the arc •f the fe&or, and the product is the area. **RULE 2. As 360 is to the degrees in the arc of the** fe£tor, fo is the. whole area of the circle to the area of the fedor. Nate. For the femieircle take... | |
| Charles Hutton - Mathematics - 1807
...firstTrule to problem 9, for the whole circle. RULE II. Compute the area of the whole circle : then say, **as 360 is to the degrees in the arc of the sector, so is the** area of the whole circle, to the area of the sector. This is evident, because the sector is proportional... | |
| Charles Hutton - Mathematics - 1811
...rule to problem 9, for the whole circle. RULE II. Compute the area of the whole circle : then say, **as 360 is to the degrees in the arc of the sector, so is the** area of the whole circle, to the area of the sector. This is evident, because the sector is proportional... | |
| Thomas Keith - 1817
...the arc by the radius of the circle, and the product is the area of the si'ctor. RUI.F. II. As 36() **is to the degrees in the arc of the sector, so is the** are* of the whole circle to the area of the sector. Example 1. Let ADBE be the sector of a circle less... | |
| Anthony Nesbit - Measurement - 1824 - 434 pages
...chord of half the arc 45 feet, and the radius 37 feet 6 inches? Ans. 2.617ft. 10 in. 6 pa, RULE II. **As 360 is to the degrees in the arc of the sector, so is the** area of the whole circle to the area of the sector. Kate I. The area of a semicircle, a quadrant, 4.c.... | |
| John Nicholson - Electronic book - 1825 - 795 pages
...Rule\. Multiply the radius, or half the diameter, by half the arc of the sector, for the area. Or take ^ **of the product of the diameter and arc of the sector....Rule 2. As 360 is to the degrees in the arc of the** lector, «o it the whole area of the circle, to the area of the sector. Ex. What is the area of the... | |
| John Nicholson - Industries - 1825 - 795 pages
...the diameter, by half the arc of the sector, for the area. Or take £ of the product of the diaineter **and arc of the sector. Note. The arc may be found...As 360 is to the degrees in the arc of the sector,** go is the whole area of the circle, to the area of tbe soctor. Ex. What is the area of the sector CAB,... | |
| John Nicholson (civil engineer.) - Great Britain - 1825 - 795 pages
...Multiply the radius, or half the diauieter, by half the arc of the sector, for the area. Or take £ **of the product of the diameter and arc of the sector....The arc may be found by problem 10. Rule 2. As 360** i» to the degrees in the arc of the sector, to i» the whole area of the circle, to the area of the... | |
| John Nicholson (Civil engineer) - Building - 1830 - 182 pages
.... Multiply the radius, or half the diameter, by half the arc of the sector, for the area. Or take $ **of the product of the diameter and arc of the sector....360 is to the degrees in the arc of the sector, so** U the whole area .of the circle, to the area of the sector. Ex. What is the area of the sector CAB,... | |
| |