 | Mathematics - 1801 - 658 pages
...'Multiply the radius, or half the diameter, by half the arc of the sector for the area. Or, take •£ of the product of the diameter and arc of the sector. NOTE. The arc may be found by Problem X. •c •"—" • RULE 2.f As 360 is to the degrees in the arc of the sector, so is the whole area... | |
 | Thomas Hodson - Education - 1806 - 576 pages
...CIRCLE. Fig.22. RULE i. Multiply the radius by half the arc •f the fe&or, and the product is the area. RULE 2. As 360 is to the degrees in the arc of the fe£tor, fo is the. whole area of the circle to the area of the fedor. Nate. For the femieircle take... | |
 | Charles Hutton - Mathematics - 1807 - 464 pages
...firstTrule to problem 9, for the whole circle. RULE II. Compute the area of the whole circle : then say, as 360 is to the degrees in the arc of the sector, so is the area of the whole circle, to the area of the sector. This is evident, because the sector is proportional... | |
 | Charles Hutton - Mathematics - 1811 - 442 pages
...rule to problem 9, for the whole circle. RULE II. Compute the area of the whole circle : then say, as 360 is to the degrees in the arc of the sector, so is the area of the whole circle, to the area of the sector. This is evident, because the sector is proportional... | |
 | Thomas Keith - 1817 - 306 pages
...the arc by the radius of the circle, and the product is the area of the si'ctor. RUI.F. II. As 36() is to the degrees in the arc of the sector, so is the are* of the whole circle to the area of the sector. Example 1. Let ADBE be the sector of a circle less... | |
 | Anthony Nesbit - Surveying - 1824 - 476 pages
...chord of half the arc 45 feet, and the radius 37 feet 6 inches? Ans. 2.617ft. 10 in. 6 pa, RULE II. As 360 is to the degrees in the arc of the sector, so is the area of the whole circle to the area of the sector. Kate I. The area of a semicircle, a quadrant, 4.c.... | |
 | John Nicholson - Machinery - 1825 - 838 pages
...Rule\. Multiply the radius, or half the diameter, by half the arc of the sector, for the area. Or take ^ of the product of the diameter and arc of the sector....Rule 2. As 360 is to the degrees in the arc of the lector, «o it the whole area of the circle, to the area of the sector. Ex. What is the area of the... | |
 | John Nicholson - Machinery - 1825 - 822 pages
...the diameter, by half the arc of the sector, for the area. Or take £ of the product of the diaineter and arc of the sector. Note. The arc may be found...As 360 is to the degrees in the arc of the sector, go is the whole area of the circle, to the area of tbe soctor. Ex. What is the area of the sector CAB,... | |
 | John Nicholson (civil engineer.) - Great Britain - 1825 - 1008 pages
...Multiply the radius, or half the diauieter, by half the arc of the sector, for the area. Or take £ of the product of the diameter and arc of the sector....The arc may be found by problem 10. Rule 2. As 360 i» to the degrees in the arc of the sector, to i» the whole area of the circle, to the area of the... | |
 | John Nicholson (Civil engineer) - Building - 1830 - 240 pages
.... Multiply the radius, or half the diameter, by half the arc of the sector, for the area. Or take $ of the product of the diameter and arc of the sector....360 is to the degrees in the arc of the sector, so U the whole area .of the circle, to the area of the sector. Ex. What is the area of the sector CAB,... | |
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As 360 is to the degrees in the arc of the sector, so is the area of the whole circle to the area of the sector. 
