 | George Alexander Gibson - Calculus - 1901 - 492 pages
...maximum the arc is double the radius, and that the maximum area is equal to the square on the radius. 8. From a given circular sheet of metal it is required...be formed into a conical vessel of maximum capacity ; show that the angle removed must be 2(1 -^v/6)ir radians (66° 41). 9. Draw a line through the vertex... | |
 | George Alexander Gibson - Calculus - 1901 - 490 pages
...maximum the arc is double the radius, and that the maximum irea is equal to the square on the radius. 8. From a given circular sheet of metal it is required to cut out a lector so that the remainder can be formed into a conical vessel of maximum capacity ; show that the... | |
 | Daniel Alexander Murray - Calculus - 1903 - 512 pages
...sides : if the inner surface is the least possible, what is the ratio of the depth to the width ? 20. From a given circular sheet of metal it is required...be formed into a conical vessel of maximum capacity : show that the angle of the sector removed must be about 00°. 21. In a submarine telegraph cable... | |
 | George Alexander Gibson - Calculus - 1906 - 252 pages
...maximum the arc is double the radius, and that the maximum area is equal to the square on the radius. 47. From a given circular sheet of metal it is required...be formed into a conical vessel of maximum capacity ; show that the angle of the sector removed must be 2(1 - JV6)T radians (about 60° 4'). In examples... | |
 | Daniel Alexander Murray - Calculus - 1908 - 522 pages
...sides : if the inner surface is the least possible, what is the ratio of the depth to the width ? 20. From a given circular sheet of metal it is required...be formed into a conical vessel of maximum capacity : show that the angle of the sector removed must be about 60°. 21. In a submarine telegraph cable... | |
 | Great Britain. Board of Education - Mathematics - 1912 - 632 pages
...Investigate a method for finding the maximum and minimum values of a function of a single variable. From a given circular sheet of metal it is required...remainder can be formed into a conical vessel of maximum volume. Show that the angle of the sector removed must be about 66°. 6. Prove the formula {'+(2)'}'... | |
 | Great Britain. Board of Education - Education - 1912 - 1044 pages
...values of a function of a single variable. From a given circular sheet of metal it is required to out out a sector so that the remainder can be formed into a conical vessel of maximum volume. Show that the angle of the sector removed must be about 66°. 6. Prove the formula ,_{'+(£)•}'... | |
 | J.V. Subrahmanyan - 2004 - 1128 pages
...(i)- (ii) gives -35a + 5b- 5c = — Substituting for b and с : с = 18 (ü) 19 dm-w S ЯГ 5IO (8) From a given circular sheet of metal it is required...capacity. Prove that the angle of the sector removed can be about 66° Solution : If arc AB is removed, the remaining part is sector ACB where L ACB is... | |
 | 556 pages
...greatest surface for a given volume has an altitude equal to *J'l times the diameter of the base. 11. From a given circular sheet of metal it is required...the angle of the sector removed must be about 66°. 12. An open rectangular tank is to contain a given volume of water, find what must be its proportions... | |
 | 558 pages
...greatest surface for a given volume has an altitude equal to *J2 times the diameter of the base. 11. From a given circular sheet of metal it is required...the angle of the sector removed must be about 66°. 12. An open rectangular tank is to contain a given volume of water, find what must be its proportions... | |
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From a given circular sheet of metal it is required to cut out a sector so that the remainder can be formed into a conical vessel of maximum capacity ; prove that the angle of the sector removed must be about 66°. 