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12 feet 12 inches 20 feet 9 feet ABCD altitude axes axis base body breadth bushel called capacity centre chord circle whose diameter circular circum circumference circumscribed cone contained contents convex surface Cube Root cubic inches cylinder cylindrical ring decimal difference divide edge ellipse ends entire surface equal equilateral EXAMPLE feet 6 inches feet long figure find the area find the Solidity foot frustrum gallon give given greater half Hence hexagon inner diameter land lateral surface length less linear mathematics measure miles multiply nearly number of sides number of square obtained OPERATION parallel parallelogram pentagonal perimeter perpendicular perpendicular height plane polygon pounds prism PROBLEM pyramid quarters radius ratio regular Required the area Rule Rule.—Multiply sector segment sides slant height sphere square feet square root thickness triangle triangular upper wedge whole wide yards zone
Page 53 - RULE. Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Page 79 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 80 - A zone is a portion of the surface of a sphere included between two parallel planes.
Page 90 - ... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents.
Page 49 - From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly.
Page 72 - RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
Page 51 - As 360 degrees is to the number of degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Page 91 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.